What are the solutions to the equation 9-6x+x^2=0 ?

The solutions to the equation 9-6x+x^2=0 are x=3

Find the zeros of 9-6x+x^2=0

The zeros of 9-6x+x^2=0 are x=3

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9 - 6 x + x^{2} = 0

x = 3

Solution steps

9 - 6 x + x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

- 96.52131 + 3.06658 \cdot x - 0.02412 \cdot x^{2} = 0

(x - 11)^{2} = 2

- 6 x^{2} + 2 x + 4 = 0

b^{2} - 36 = 0

2 y^{2} + y = 6

What are the solutions to the equation 9-6x+x^2=0 ?
The solutions to the equation 9-6x+x^2=0 are x=3
Find the zeros of 9-6x+x^2=0
The zeros of 9-6x+x^2=0 are x=3