What are the solutions to the equation -6x^2+2x+3=0 ?

The solutions to the equation -6x^2+2x+3=0 are x=-(-1+sqrt(19))/6 ,x=(1+sqrt(19))/6

Find the zeros of -6x^2+2x+3=0

The zeros of -6x^2+2x+3=0 are x=-(-1+sqrt(19))/6 ,x=(1+sqrt(19))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 6 x^{2} + 2 x + 3 = 0

x = - \frac{- 1 + 19}{6}, x = \frac{1 + 19}{6}

Decimal Notation

x = - 0.55981 \dots, x = 0.89314 \dots

Solution steps

- 6 x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 6 ) \cdot 3}{2 ( - 6 )}

2^{2} - 4 (- 6) \cdot 3 = 219

x_{1, 2} = \frac{- 2 \pm 2 19}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 19}{2 ( - 6 )}, x_{2} = \frac{- 2 - 2 19}{2 ( - 6 )}

x = \frac{- 2 + 2 19}{2 ( - 6 )} : - \frac{- 1 + 19}{6}

x = \frac{- 2 - 2 19}{2 ( - 6 )} : \frac{1 + 19}{6}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 19}{6}, x = \frac{1 + 19}{6}

x, x^{2} + y^{2} + z^{2} - 4 x + 6 y + 2 z = 11

7 x^{2} + 4 x + 1 = 0

2 x^{2} + 7 x - 51 = - 2

x, x^{2} - 1 = y (x^{2} + 4)

x^{2} - 4 x + 70

What are the solutions to the equation -6x^2+2x+3=0 ?
The solutions to the equation -6x^2+2x+3=0 are x=-(-1+sqrt(19))/6 ,x=(1+sqrt(19))/6
Find the zeros of -6x^2+2x+3=0
The zeros of -6x^2+2x+3=0 are x=-(-1+sqrt(19))/6 ,x=(1+sqrt(19))/6