What are the solutions to the equation y^2+5y-36=0 ?

The solutions to the equation y^2+5y-36=0 are y=4,y=-9

Find the zeros of y^2+5y-36=0

The zeros of y^2+5y-36=0 are y=4,y=-9

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y^{2} + 5 y - 36 = 0

y = 4, y = - 9

Solution steps

y^{2} + 5 y - 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 36) = 13

y_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 13}{2 \cdot 1}, y_{2} = \frac{- 5 - 13}{2 \cdot 1}

y = \frac{- 5 + 13}{2 \cdot 1} : 4

y = \frac{- 5 - 13}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

y = 4, y = - 9

(x + 1) (x + 5) = 32

(1.489 - 2.48 I)^{2} + (1.49 - 2.48 I)^{2} = 0

1.25 \cdot 1 0^{- 10} = \frac{x ^{2}}{0.5}

5 x^{2} + 2 x - 39 = 0

h, 0 = \frac{π R ^{2} - 3 π h ^{2}}{4}

What are the solutions to the equation y^2+5y-36=0 ?
The solutions to the equation y^2+5y-36=0 are y=4,y=-9
Find the zeros of y^2+5y-36=0
The zeros of y^2+5y-36=0 are y=4,y=-9