What are the solutions to the equation factor 3x^2+12=7x+32 ?

The solutions to the equation factor 3x^2+12=7x+32 are x=-5/3 ,x=4

Find the zeros of factor 3x^2+12=7x+32

The zeros of factor 3x^2+12=7x+32 are x=-5/3 ,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 12 = 7 x + 32

x = - \frac{5}{3}, x = 4

Decimal Notation

x = - 1.66666 \dots, x = 4

Solution steps

3 x^{2} + 12 = 7 x + 32

Move

32

to the left side

3 x^{2} - 20 = 7 x

Move

7 x

to the left side

3 x^{2} - 20 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 7 x - 20 = 0

Factor

3 x^{2} - 7 x - 20 : (3 x + 5) (x - 4)

(3 x + 5) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 5 = 0 or x - 4 = 0

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = 4

(x + 2) (x - 15) = 0

32 x^{2} - 16 x - 12 = 0

- 16 x^{2} + 4 x + 13 = 0

5 a^{2} - 8 a + 3 = 0

0 = 8.2 + \frac{1}{2} (9.8) t^{2}

What are the solutions to the equation factor 3x^2+12=7x+32 ?
The solutions to the equation factor 3x^2+12=7x+32 are x=-5/3 ,x=4
Find the zeros of factor 3x^2+12=7x+32
The zeros of factor 3x^2+12=7x+32 are x=-5/3 ,x=4