What are the solutions to the equation 3x^2-3x=-7 ?

The solutions to the equation 3x^2-3x=-7 are x= 1/2+i(5sqrt(3))/6 ,x= 1/2-i(5sqrt(3))/6

Find the zeros of 3x^2-3x=-7

The zeros of 3x^2-3x=-7 are x= 1/2+i(5sqrt(3))/6 ,x= 1/2-i(5sqrt(3))/6

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3 x^{2} - 3 x = - 7

x = \frac{1}{2} + i \frac{5 3}{6}, x = \frac{1}{2} - i \frac{5 3}{6}

Solution steps

3 x^{2} - 3 x = - 7

Move

7

to the left side

3 x^{2} - 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

(- 3)^{2} - 4 \cdot 3 \cdot 7 : 53 i

x_{1, 2} = \frac{- ( - 3 ) \pm 5 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5 3 i}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 5 3 i}{2 \cdot 3}

x = \frac{- ( - 3 ) + 5 3 i}{2 \cdot 3} : \frac{1}{2} + i \frac{5 3}{6}

x = \frac{- ( - 3 ) - 5 3 i}{2 \cdot 3} : \frac{1}{2} - i \frac{5 3}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{5 3}{6}, x = \frac{1}{2} - i \frac{5 3}{6}

x, x^{2} + 8 x - 1 = 0

8 x^{2} - 17 x = - 16

3 w^{2} = 12

- 16 t^{2} + 64 t + 16 = 0

x^{2} - 2 x = 15

What are the solutions to the equation 3x^2-3x=-7 ?
The solutions to the equation 3x^2-3x=-7 are x= 1/2+i(5sqrt(3))/6 ,x= 1/2-i(5sqrt(3))/6
Find the zeros of 3x^2-3x=-7
The zeros of 3x^2-3x=-7 are x= 1/2+i(5sqrt(3))/6 ,x= 1/2-i(5sqrt(3))/6