What are the solutions to the equation -x^2+2x+3=-6x ?

The solutions to the equation -x^2+2x+3=-6x are x=4-sqrt(19),x=4+sqrt(19)

Find the zeros of -x^2+2x+3=-6x

The zeros of -x^2+2x+3=-6x are x=4-sqrt(19),x=4+sqrt(19)

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- x^{2} + 2 x + 3 = - 6 x

x = 4 - 19, x = 4 + 19

Decimal Notation

x = - 0.35889 \dots, x = 8.35889 \dots

Solution steps

- x^{2} + 2 x + 3 = - 6 x

Move

6 x

to the left side

- x^{2} + 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 3 = 219

x_{1, 2} = \frac{- 8 \pm 2 19}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 19}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 19}{2 ( - 1 )}

x = \frac{- 8 + 2 19}{2 ( - 1 )} : 4 - 19

x = \frac{- 8 - 2 19}{2 ( - 1 )} : 4 + 19

The solutions to the quadratic equation are:

x = 4 - 19, x = 4 + 19

36 k^{2} = 25

2 x^{2} - 4 x + 3 = 0

y^{2} - 6 y + 3 = 0

y = 2.49 \cdot 1 0^{- 3} (1 - \frac{0.5714 - 2000 y}{- 2})^{2}

x^{2} = 1 2^{2} + 1 2^{2}

What are the solutions to the equation -x^2+2x+3=-6x ?
The solutions to the equation -x^2+2x+3=-6x are x=4-sqrt(19),x=4+sqrt(19)
Find the zeros of -x^2+2x+3=-6x
The zeros of -x^2+2x+3=-6x are x=4-sqrt(19),x=4+sqrt(19)