What are the solutions to the equation x^2=1-8x ?

The solutions to the equation x^2=1-8x are x=-4+sqrt(17),x=-4-sqrt(17)

Find the zeros of x^2=1-8x

The zeros of x^2=1-8x are x=-4+sqrt(17),x=-4-sqrt(17)

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x^{2} = 1 - 8 x

x = - 4 + 17, x = - 4 - 17

Decimal Notation

x = 0.12310 \dots, x = - 8.12310 \dots

Solution steps

x^{2} = 1 - 8 x

Move

8 x

to the left side

x^{2} + 8 x = 1

Move

1

to the left side

x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 1) = 217

x_{1, 2} = \frac{- 8 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 17}{2 \cdot 1}

x = \frac{- 8 + 2 17}{2 \cdot 1} : - 4 + 17

x = \frac{- 8 - 2 17}{2 \cdot 1} : - 4 - 17

The solutions to the quadratic equation are:

x = - 4 + 17, x = - 4 - 17

2 - x^{2} = x^{2} - 16

x, - 9 x^{2} - 9 y^{2} + z^{2} + 6 z + 18 = 0

x^{2} = \frac{- 1}{- 9}

6 x^{2} + 144 = 0

c (x) = 0.3 x^{2} - 144 x + 30178

What are the solutions to the equation x^2=1-8x ?
The solutions to the equation x^2=1-8x are x=-4+sqrt(17),x=-4-sqrt(17)
Find the zeros of x^2=1-8x
The zeros of x^2=1-8x are x=-4+sqrt(17),x=-4-sqrt(17)