What are the solutions to the equation solvefor x,4xy-x^2-3x=0 ?

The solutions to the equation solvefor x,4xy-x^2-3x=0 are x=0,x=4y-3

Find the zeros of solvefor x,4xy-x^2-3x=0

The zeros of solvefor x,4xy-x^2-3x=0 are x=0,x=4y-3

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solve for

x, 4 x y - x^{2} - 3 x = 0

x = 0, x = 4 y - 3

Solution steps

4 x y - x^{2} - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + (4 y - 3) x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 4 y - 3 ) \pm ( 4 y - 3 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

Simplify

(4 y - 3)^{2} - 4 (- 1) \cdot 0 : 4 y - 3

x_{1, 2} = \frac{- ( 4 y - 3 ) \pm ( 4 y - 3 )}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( 4 y - 3 ) + 4 y - 3}{2 ( - 1 )}, x_{2} = \frac{- ( 4 y - 3 ) - ( 4 y - 3 )}{2 ( - 1 )}

x = \frac{- ( 4 y - 3 ) + 4 y - 3}{2 ( - 1 )} : 0

x = \frac{- ( 4 y - 3 ) - ( 4 y - 3 )}{2 ( - 1 )} : 4 y - 3

The solutions to the quadratic equation are:

x = 0, x = 4 y - 3

A (x) = x (\frac{126 - 2 x}{3})

7^{2} + 1 2^{2} = c^{2}

12 k (2 k + 11) = 12 (2 k + 12)

- x^{2} - x - 8 = 0

2 x^{2} - 11 x = - 12

What are the solutions to the equation solvefor x,4xy-x^2-3x=0 ?
The solutions to the equation solvefor x,4xy-x^2-3x=0 are x=0,x=4y-3
Find the zeros of solvefor x,4xy-x^2-3x=0
The zeros of solvefor x,4xy-x^2-3x=0 are x=0,x=4y-3