What are the solutions to the equation -16x^2+112x+84=0 ?

The solutions to the equation -16x^2+112x+84=0 are x=-(-7+sqrt(70))/2 ,x=(7+sqrt(70))/2

Find the zeros of -16x^2+112x+84=0

The zeros of -16x^2+112x+84=0 are x=-(-7+sqrt(70))/2 ,x=(7+sqrt(70))/2

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- 16 x^{2} + 112 x + 84 = 0

x = - \frac{- 7 + 70}{2}, x = \frac{7 + 70}{2}

Decimal Notation

x = - 0.68330 \dots, x = 7.68330 \dots

Solution steps

- 16 x^{2} + 112 x + 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 112 \pm 11 2 ^{2} - 4 ( - 16 ) \cdot 84}{2 ( - 16 )}

11 2^{2} - 4 (- 16) \cdot 84 = 1670

x_{1, 2} = \frac{- 112 \pm 16 70}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 112 + 16 70}{2 ( - 16 )}, x_{2} = \frac{- 112 - 16 70}{2 ( - 16 )}

x = \frac{- 112 + 16 70}{2 ( - 16 )} : - \frac{- 7 + 70}{2}

x = \frac{- 112 - 16 70}{2 ( - 16 )} : \frac{7 + 70}{2}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 70}{2}, x = \frac{7 + 70}{2}

\frac{1}{2} x^{2} + x - 12 = 0

18 x^{2} - 3 x - 8 = 0

8^{2} + 7^{2} = x^{2}

15 x - 20 = 6 x (x + 2) + (- x + 3)

p^{2} + \frac{p}{3} = \frac{1}{6}

What are the solutions to the equation -16x^2+112x+84=0 ?
The solutions to the equation -16x^2+112x+84=0 are x=-(-7+sqrt(70))/2 ,x=(7+sqrt(70))/2
Find the zeros of -16x^2+112x+84=0
The zeros of -16x^2+112x+84=0 are x=-(-7+sqrt(70))/2 ,x=(7+sqrt(70))/2