What are the solutions to the equation 0=2x^2-2x-4 ?

The solutions to the equation 0=2x^2-2x-4 are x=2,x=-1

Find the zeros of 0=2x^2-2x-4

The zeros of 0=2x^2-2x-4 are x=2,x=-1

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0 = 2 x^{2} - 2 x - 4

x = 2, x = - 1

Solution steps

0 = 2 x^{2} - 2 x - 4

Switch sides

2 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 4) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 2}

x = \frac{- ( - 2 ) + 6}{2 \cdot 2} : 2

x = \frac{- ( - 2 ) - 6}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

(x + 4)^{2} - (x + 4) - 6 = 0

q, z (1 - q^{2}) = 2 (a q x + q y)

- x (x - 6) = 0

3 x (x + 4) + 6 (x^{2} - 1) = - 10

c, m \cdot b \cdot a = n \cdot k \cdot c^{2} \cdot s \cdot p + m \cdot c \cdot a

What are the solutions to the equation 0=2x^2-2x-4 ?
The solutions to the equation 0=2x^2-2x-4 are x=2,x=-1
Find the zeros of 0=2x^2-2x-4
The zeros of 0=2x^2-2x-4 are x=2,x=-1