What are the solutions to the equation x^2-8x=13 ?

The solutions to the equation x^2-8x=13 are x=4+sqrt(29),x=4-sqrt(29)

Find the zeros of x^2-8x=13

The zeros of x^2-8x=13 are x=4+sqrt(29),x=4-sqrt(29)

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x^{2} - 8 x = 13

x = 4 + 29, x = 4 - 29

Solution steps

x^{2} - 8 x = 13

Move

13

to the left side

x^{2} - 8 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 13) = 229

x_{1, 2} = \frac{- ( - 8 ) \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 29}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 29}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 29}{2 \cdot 1} : 4 + 29

x = \frac{- ( - 8 ) - 2 29}{2 \cdot 1} : 4 - 29

The solutions to the quadratic equation are:

x = 4 + 29, x = 4 - 29

\frac{( 3 + i ) ^{10}}{1 + i}

\frac{5 !}{4 ! 1 !}

\frac{1}{12} + \frac{2}{9}

x^{2} > 4 (x + 8)

5 x^{2} + 10 x + 500

What are the solutions to the equation x^2-8x=13 ?
The solutions to the equation x^2-8x=13 are x=4+sqrt(29),x=4-sqrt(29)
Find the zeros of x^2-8x=13
The zeros of x^2-8x=13 are x=4+sqrt(29),x=4-sqrt(29)