What are the solutions to the equation completesquare x^2+7x+18 ?

The solutions to the equation completesquare x^2+7x+18 are (x+7/2)^2+23/4

Find the zeros of completesquare x^2+7x+18

The zeros of completesquare x^2+7x+18 are (x+7/2)^2+23/4

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complete the square

x^{2} + 7 x + 18

(x + \frac{7}{2})^{2} + \frac{23}{4}

Solution steps

x^{2} + 7 x + 18

Write

x^{2} + 7 x + 18

in the form:

x^{2} + 2 a x + a^{2}

2 a = 7 : a = \frac{7}{2}

Add and subtract

(\frac{7}{2})^{2}

x^{2} + 7 x + 18 + (\frac{7}{2})^{2} - (\frac{7}{2})^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 7 x + (\frac{7}{2})^{2} = (x + \frac{7}{2})^{2}

(x + \frac{7}{2})^{2} + 18 - (\frac{7}{2})^{2}

Simplify

(x + \frac{7}{2})^{2} + \frac{23}{4}

2 x^{2} - 5 x - 150 = 0

(x - 1)^{2} = 5^{4}

x^{2} - 8 x + 16 = 3

75 = \frac{1}{2} (5) v^{2}

(x - 3) (4 x + 1) = 0

What are the solutions to the equation completesquare x^2+7x+18 ?
The solutions to the equation completesquare x^2+7x+18 are (x+7/2)^2+23/4
Find the zeros of completesquare x^2+7x+18
The zeros of completesquare x^2+7x+18 are (x+7/2)^2+23/4