What are the solutions to the equation 4x^2-12x-9+3=0 ?

The solutions to the equation 4x^2-12x-9+3=0 are x=(3+sqrt(15))/2 ,x=(3-sqrt(15))/2

Find the zeros of 4x^2-12x-9+3=0

The zeros of 4x^2-12x-9+3=0 are x=(3+sqrt(15))/2 ,x=(3-sqrt(15))/2

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4 x^{2} - 12 x - 9 + 3 = 0

x = \frac{3 + 15}{2}, x = \frac{3 - 15}{2}

Decimal Notation

x = 3.43649 \dots, x = - 0.43649 \dots

Solution steps

4 x^{2} - 12 x - 9 + 3 = 0

Refine

4 x^{2} - 12 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 6) = 415

x_{1, 2} = \frac{- ( - 12 ) \pm 4 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 15}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 4 15}{2 \cdot 4}

x = \frac{- ( - 12 ) + 4 15}{2 \cdot 4} : \frac{3 + 15}{2}

x = \frac{- ( - 12 ) - 4 15}{2 \cdot 4} : \frac{3 - 15}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 15}{2}, x = \frac{3 - 15}{2}

1 0^{2} + 10 0^{2} = c^{2}

t, 5 t^{2} - 9 = 0

s^{2}

25 x^{2} + 5 x = 0

a^{2} + 4 8^{2} = 5 2^{2}

What are the solutions to the equation 4x^2-12x-9+3=0 ?
The solutions to the equation 4x^2-12x-9+3=0 are x=(3+sqrt(15))/2 ,x=(3-sqrt(15))/2
Find the zeros of 4x^2-12x-9+3=0
The zeros of 4x^2-12x-9+3=0 are x=(3+sqrt(15))/2 ,x=(3-sqrt(15))/2