What are the solutions to the equation x^2-6x+9=2 ?

The solutions to the equation x^2-6x+9=2 are x=3+sqrt(2),x=3-sqrt(2)

Find the zeros of x^2-6x+9=2

The zeros of x^2-6x+9=2 are x=3+sqrt(2),x=3-sqrt(2)

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x^{2} - 6 x + 9 = 2

x = 3 + 2, x = 3 - 2

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

x^{2} - 6 x + 9 = 2

Move

2

to the left side

x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 7 = 22

x_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 2}{2 \cdot 1} : 3 + 2

x = \frac{- ( - 6 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

x = 3 + 2, x = 3 - 2

2 s^{2} + s + 1 = 0

x^{2} + 8 + 3

0.81307831 x^{2} - 71.248 + 1600 = 0

- 4 x^{2} - 28 x = 0

648 - 6 x^{2} = 0

What are the solutions to the equation x^2-6x+9=2 ?
The solutions to the equation x^2-6x+9=2 are x=3+sqrt(2),x=3-sqrt(2)
Find the zeros of x^2-6x+9=2
The zeros of x^2-6x+9=2 are x=3+sqrt(2),x=3-sqrt(2)