What are the solutions to the equation n^2-18n+91=0 ?

The solutions to the equation n^2-18n+91=0 are n=9+sqrt(10)i,n=9-sqrt(10)i

Find the zeros of n^2-18n+91=0

The zeros of n^2-18n+91=0 are n=9+sqrt(10)i,n=9-sqrt(10)i

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n^{2} - 18 n + 91 = 0

n = 9 + 10 i, n = 9 - 10 i

Solution steps

n^{2} - 18 n + 91 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 91}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 91 : 210 i

n_{1, 2} = \frac{- ( - 18 ) \pm 2 10 i}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 18 ) + 2 10 i}{2 \cdot 1}, n_{2} = \frac{- ( - 18 ) - 2 10 i}{2 \cdot 1}

n = \frac{- ( - 18 ) + 2 10 i}{2 \cdot 1} : 9 + 10 i

n = \frac{- ( - 18 ) - 2 10 i}{2 \cdot 1} : 9 - 10 i

The solutions to the quadratic equation are:

n = 9 + 10 i, n = 9 - 10 i

x, k x^{2} + 8 x + 2 k = 0

x, x^{2} - 4 x y - 2 y^{2} - 3 = 0

2 (x + 4) = - (2 x - 3)^{2}

0 = - 4.9 x^{2} + 30 x

5 s^{2} + 8 s - 8 = 0

What are the solutions to the equation n^2-18n+91=0 ?
The solutions to the equation n^2-18n+91=0 are n=9+sqrt(10)i,n=9-sqrt(10)i
Find the zeros of n^2-18n+91=0
The zeros of n^2-18n+91=0 are n=9+sqrt(10)i,n=9-sqrt(10)i