What are the solutions to the equation 36=-4x^2-50 ?

The solutions to the equation 36=-4x^2-50 are x=sqrt(43/2)i,x=-sqrt(43/2)i

Find the zeros of 36=-4x^2-50

The zeros of 36=-4x^2-50 are x=sqrt(43/2)i,x=-sqrt(43/2)i

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36 = - 4 x^{2} - 50

x = \frac{43}{2} i, x = - \frac{43}{2} i

Solution steps

36 = - 4 x^{2} - 50

Switch sides

- 4 x^{2} - 50 = 36

Move

50

to the right side

- 4 x^{2} = 86

Divide both sides by

- 4

x^{2} = - \frac{43}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{43}{2}, x = - - \frac{43}{2}

- \frac{43}{2} = \frac{43}{2} i

- - \frac{43}{2} = - \frac{43}{2} i

x = \frac{43}{2} i, x = - \frac{43}{2} i

x, x^{2} - 8 x y + 25 y^{2} = 81

x^{2} = 2025

5.9 x^{2} + 3 x - 2.7 = 0

b^{2} - 13 b = - 40

13 x^{2} + 7100 x + 420000 = 0

What are the solutions to the equation 36=-4x^2-50 ?
The solutions to the equation 36=-4x^2-50 are x=sqrt(43/2)i,x=-sqrt(43/2)i
Find the zeros of 36=-4x^2-50
The zeros of 36=-4x^2-50 are x=sqrt(43/2)i,x=-sqrt(43/2)i