What are the solutions to the equation 28x^2+180x=-72 ?

The solutions to the equation 28x^2+180x=-72 are x=-3/7 ,x=-6

Find the zeros of 28x^2+180x=-72

The zeros of 28x^2+180x=-72 are x=-3/7 ,x=-6

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28 x^{2} + 180 x = - 72

x = - \frac{3}{7}, x = - 6

Decimal Notation

x = - 0.42857 \dots, x = - 6

Solution steps

28 x^{2} + 180 x = - 72

Move

72

to the left side

28 x^{2} + 180 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 180 \pm 18 0 ^{2} - 4 \cdot 28 \cdot 72}{2 \cdot 28}

18 0^{2} - 4 \cdot 28 \cdot 72 = 156

x_{1, 2} = \frac{- 180 \pm 156}{2 \cdot 28}

Separate the solutions

x_{1} = \frac{- 180 + 156}{2 \cdot 28}, x_{2} = \frac{- 180 - 156}{2 \cdot 28}

x = \frac{- 180 + 156}{2 \cdot 28} : - \frac{3}{7}

x = \frac{- 180 - 156}{2 \cdot 28} : - 6

The solutions to the quadratic equation are:

x = - \frac{3}{7}, x = - 6

12 x^{2} - 140 x + 250 = 0

- 3 x^{2} + 22 x - 24 = 0

x^{2} + 23 x + 22 = 0

108 x^{2} = 0

22 x^{2} + 24 = 0

What are the solutions to the equation 28x^2+180x=-72 ?
The solutions to the equation 28x^2+180x=-72 are x=-3/7 ,x=-6
Find the zeros of 28x^2+180x=-72
The zeros of 28x^2+180x=-72 are x=-3/7 ,x=-6