What are the solutions to the equation 1.06=(1+x)^2 ?

The solutions to the equation 1.06=(1+x)^2 are x=0.02956…,x=-2.02956…

Find the zeros of 1.06=(1+x)^2

The zeros of 1.06=(1+x)^2 are x=0.02956…,x=-2.02956…

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1.06 = (1 + x)^{2}

x = 0.02956 \dots, x = - 2.02956 \dots

Solution steps

1.06 = (1 + x)^{2}

Switch sides

(1 + x)^{2} = 1.06

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 + x = 1.06 : x = 0.02956 \dots

Solve

1 + x = - 1.06 : x = - 2.02956 \dots

The solutions to the quadratic equation are:

x = 0.02956 \dots, x = - 2.02956 \dots

0.4 m^{2} + 1000 = 0

(\frac{3}{4})^{2} + x^{2} = 1

x^{2} - 5 x + 3 = - 7 x + 11

- 3 x^{2} - 2 x + 5 = 0

(x - 4)^{2} + (x - 3)^{2} = (x - 2)^{2}

What are the solutions to the equation 1.06=(1+x)^2 ?
The solutions to the equation 1.06=(1+x)^2 are x=0.02956…,x=-2.02956…
Find the zeros of 1.06=(1+x)^2
The zeros of 1.06=(1+x)^2 are x=0.02956…,x=-2.02956…