What are the solutions to the equation 0=-16t^2+1454 ?

The solutions to the equation 0=-16t^2+1454 are t=(sqrt(727))/(2sqrt(2)),t=-(sqrt(727))/(2sqrt(2))

Find the zeros of 0=-16t^2+1454

The zeros of 0=-16t^2+1454 are t=(sqrt(727))/(2sqrt(2)),t=-(sqrt(727))/(2sqrt(2))

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0 = - 16 t^{2} + 1454

t = \frac{727}{2 2}, t = - \frac{727}{2 2}

Decimal Notation

t = 9.53283 \dots, t = - 9.53283 \dots

Solution steps

0 = - 16 t^{2} + 1454

Switch sides

- 16 t^{2} + 1454 = 0

Move

1454

to the right side

- 16 t^{2} = - 1454

Divide both sides by

- 16

t^{2} = \frac{727}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{727}{8}, t = - \frac{727}{8}

\frac{727}{8} = \frac{727}{2 2}

- \frac{727}{8} = - \frac{727}{2 2}

t = \frac{727}{2 2}, t = - \frac{727}{2 2}

6 x^{2} - 2 x + 8 = 0

9 x^{2} + 6 = 2 x

2 x^{2} + x - 528 = 0

x^{2} + 10 x + 27 = 0

x^{2} + 4 x = 65

What are the solutions to the equation 0=-16t^2+1454 ?
The solutions to the equation 0=-16t^2+1454 are t=(sqrt(727))/(2sqrt(2)),t=-(sqrt(727))/(2sqrt(2))
Find the zeros of 0=-16t^2+1454
The zeros of 0=-16t^2+1454 are t=(sqrt(727))/(2sqrt(2)),t=-(sqrt(727))/(2sqrt(2))