What are the solutions to the equation 3(x+2)^2-4=11 ?

The solutions to the equation 3(x+2)^2-4=11 are x=sqrt(5)-2,x=-sqrt(5)-2

Find the zeros of 3(x+2)^2-4=11

The zeros of 3(x+2)^2-4=11 are x=sqrt(5)-2,x=-sqrt(5)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (x + 2)^{2} - 4 = 11

x = 5 - 2, x = - 5 - 2

Decimal Notation

x = 0.23606 \dots, x = - 4.23606 \dots

Solution steps

3 (x + 2)^{2} - 4 = 11

Move

4

to the right side

3 (x + 2)^{2} = 15

Divide both sides by

3

(x + 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 5 : x = 5 - 2

Solve

x + 2 = - 5 : x = - 5 - 2

The solutions to the quadratic equation are:

x = 5 - 2, x = - 5 - 2

x (2 x - 4) - 100 = 4 (6 - x) - 17

2 x^{2} - 3 x - 42 = 2

9 x^{2} - 25 x + 16 = 0

n^{2} - 10 = 3 n

x^{2} = x + 6

What are the solutions to the equation 3(x+2)^2-4=11 ?
The solutions to the equation 3(x+2)^2-4=11 are x=sqrt(5)-2,x=-sqrt(5)-2
Find the zeros of 3(x+2)^2-4=11
The zeros of 3(x+2)^2-4=11 are x=sqrt(5)-2,x=-sqrt(5)-2