What are the solutions to the equation x(x+5)=104 ?

The solutions to the equation x(x+5)=104 are x=8,x=-13

Find the zeros of x(x+5)=104

The zeros of x(x+5)=104 are x=8,x=-13

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x (x + 5) = 104

x = 8, x = - 13

Solution steps

x (x + 5) = 104

Expand

x (x + 5) : x^{2} + 5 x

x^{2} + 5 x = 104

Move

104

to the left side

x^{2} + 5 x - 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 104 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 104) = 21

x_{1, 2} = \frac{- 5 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 21}{2 \cdot 1}, x_{2} = \frac{- 5 - 21}{2 \cdot 1}

x = \frac{- 5 + 21}{2 \cdot 1} : 8

x = \frac{- 5 - 21}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 8, x = - 13

2 x^{2} + b x + 3 = 0

x^{2} + 5.71 \cdot 1 0^{- 12} x - 5.71 \cdot 1 0^{- 10} = 0

a, x^{2} + y^{2} - x y = a^{2}

y^{2} - 2 y + 1 = y + 1

D, (D^{2} - \frac{3}{x} D + \frac{3}{x ^{2}}) y = 2 x - 1

What are the solutions to the equation x(x+5)=104 ?
The solutions to the equation x(x+5)=104 are x=8,x=-13
Find the zeros of x(x+5)=104
The zeros of x(x+5)=104 are x=8,x=-13