What are the solutions to the equation 0=-16t^2+224t+168 ?

The solutions to the equation 0=-16t^2+224t+168 are t=-(-14+sqrt(238))/2 ,t=(14+sqrt(238))/2

Find the zeros of 0=-16t^2+224t+168

The zeros of 0=-16t^2+224t+168 are t=-(-14+sqrt(238))/2 ,t=(14+sqrt(238))/2

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0 = - 16 t^{2} + 224 t + 168

t = - \frac{- 14 + 238}{2}, t = \frac{14 + 238}{2}

Decimal Notation

t = - 0.71362 \dots, t = 14.71362 \dots

Solution steps

0 = - 16 t^{2} + 224 t + 168

Switch sides

- 16 t^{2} + 224 t + 168 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 224 \pm 22 4 ^{2} - 4 ( - 16 ) \cdot 168}{2 ( - 16 )}

22 4^{2} - 4 (- 16) \cdot 168 = 16238

t_{1, 2} = \frac{- 224 \pm 16 238}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 224 + 16 238}{2 ( - 16 )}, t_{2} = \frac{- 224 - 16 238}{2 ( - 16 )}

t = \frac{- 224 + 16 238}{2 ( - 16 )} : - \frac{- 14 + 238}{2}

t = \frac{- 224 - 16 238}{2 ( - 16 )} : \frac{14 + 238}{2}

The solutions to the quadratic equation are:

t = - \frac{- 14 + 238}{2}, t = \frac{14 + 238}{2}

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2 0^{2} + 5 2^{2} = c^{2}

4 x^{2} + 9 x - 6 = 0

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What are the solutions to the equation 0=-16t^2+224t+168 ?
The solutions to the equation 0=-16t^2+224t+168 are t=-(-14+sqrt(238))/2 ,t=(14+sqrt(238))/2
Find the zeros of 0=-16t^2+224t+168
The zeros of 0=-16t^2+224t+168 are t=-(-14+sqrt(238))/2 ,t=(14+sqrt(238))/2