What are the solutions to the equation 5p^2+5p+4=0 ?

The solutions to the equation 5p^2+5p+4=0 are p=-1/2+i(sqrt(55))/(10),p=-1/2-i(sqrt(55))/(10)

Find the zeros of 5p^2+5p+4=0

The zeros of 5p^2+5p+4=0 are p=-1/2+i(sqrt(55))/(10),p=-1/2-i(sqrt(55))/(10)

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5 p^{2} + 5 p + 4 = 0

p = - \frac{1}{2} + i \frac{55}{10}, p = - \frac{1}{2} - i \frac{55}{10}

Solution steps

5 p^{2} + 5 p + 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

5^{2} - 4 \cdot 5 \cdot 4 : 55 i

p_{1, 2} = \frac{- 5 \pm 55 i}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- 5 + 55 i}{2 \cdot 5}, p_{2} = \frac{- 5 - 55 i}{2 \cdot 5}

p = \frac{- 5 + 55 i}{2 \cdot 5} : - \frac{1}{2} + i \frac{55}{10}

p = \frac{- 5 - 55 i}{2 \cdot 5} : - \frac{1}{2} - i \frac{55}{10}

The solutions to the quadratic equation are:

p = - \frac{1}{2} + i \frac{55}{10}, p = - \frac{1}{2} - i \frac{55}{10}

x^{2} + 8 x + 2 = 0

a^{2} = 1 7^{2} - 8^{2}

x^{2} - 2 x + x^{2} - 4 x = 0

(t + 4)^{2} = 16

x, x^{2} + 2 x y + y^{2} + 8 x + 8 y + 16 = 0

What are the solutions to the equation 5p^2+5p+4=0 ?
The solutions to the equation 5p^2+5p+4=0 are p=-1/2+i(sqrt(55))/(10),p=-1/2-i(sqrt(55))/(10)
Find the zeros of 5p^2+5p+4=0
The zeros of 5p^2+5p+4=0 are p=-1/2+i(sqrt(55))/(10),p=-1/2-i(sqrt(55))/(10)