What are the solutions to the equation 18x^2+6x+1=0 ?

The solutions to the equation 18x^2+6x+1=0 are x=-1/6+i 1/6 ,x=-1/6-i 1/6

Find the zeros of 18x^2+6x+1=0

The zeros of 18x^2+6x+1=0 are x=-1/6+i 1/6 ,x=-1/6-i 1/6

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18 x^{2} + 6 x + 1 = 0

x = - \frac{1}{6} + i \frac{1}{6}, x = - \frac{1}{6} - i \frac{1}{6}

Solution steps

18 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 18 \cdot 1}{2 \cdot 18}

Simplify

6^{2} - 4 \cdot 18 \cdot 1 : 6 i

x_{1, 2} = \frac{- 6 \pm 6 i}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- 6 + 6 i}{2 \cdot 18}, x_{2} = \frac{- 6 - 6 i}{2 \cdot 18}

x = \frac{- 6 + 6 i}{2 \cdot 18} : - \frac{1}{6} + i \frac{1}{6}

x = \frac{- 6 - 6 i}{2 \cdot 18} : - \frac{1}{6} - i \frac{1}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{6} + i \frac{1}{6}, x = - \frac{1}{6} - i \frac{1}{6}

z^{2} - 11 z + 24 = 0

x^{2} - 2 = 2 x + 1

3 x (x - 2) - (x - 6) = 23 (x - 6)

4 x^{2} + 2 = - 5 x - 5 x

(x - 2)^{2} + (x + 4)^{2} = 16

What are the solutions to the equation 18x^2+6x+1=0 ?
The solutions to the equation 18x^2+6x+1=0 are x=-1/6+i 1/6 ,x=-1/6-i 1/6
Find the zeros of 18x^2+6x+1=0
The zeros of 18x^2+6x+1=0 are x=-1/6+i 1/6 ,x=-1/6-i 1/6