What are the solutions to the equation -x^2=pi-2 ?

The solutions to the equation -x^2=pi-2 are x=isqrt(pi-2),x=-isqrt(pi-2)

Find the zeros of -x^2=pi-2

The zeros of -x^2=pi-2 are x=isqrt(pi-2),x=-isqrt(pi-2)

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- x^{2} = π - 2

x = i π - 2, x = - i π - 2

Solution steps

- x^{2} = π - 2

Divide both sides by

- 1

x^{2} = - π + 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - π + 2, x = - - π + 2

Simplify

- π + 2 : i π - 2

Simplify

- - π + 2 : - i π - 2

x = i π - 2, x = - i π - 2

x, t = x^{2}

12 a x^{2} + 8 a x + 12 b x + 4 b + 12 c = 0

- 7 x^{2} - 49 x = 0

x^{2} = - 2 x + 35

- 4 x^{2} = 5 x + 9

What are the solutions to the equation -x^2=pi-2 ?
The solutions to the equation -x^2=pi-2 are x=isqrt(pi-2),x=-isqrt(pi-2)
Find the zeros of -x^2=pi-2
The zeros of -x^2=pi-2 are x=isqrt(pi-2),x=-isqrt(pi-2)