What are the solutions to the equation x^2-(n-3)x-3n=0 ?

The solutions to the equation x^2-(n-3)x-3n=0 are x=n,x=-3

Find the zeros of x^2-(n-3)x-3n=0

The zeros of x^2-(n-3)x-3n=0 are x=n,x=-3

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x^{2} - (n - 3) x - 3 n = 0

x = n, x = - 3

Solution steps

x^{2} - (n - 3) x - 3 n = 0

Expand

x^{2} - (n - 3) x - 3 n : x^{2} - n x + 3 x - 3 n

x^{2} - n x + 3 x - 3 n = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + (- n + 3) x - 3 n = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - n + 3 ) \pm ( - n + 3 ) ^{2} - 4 \cdot 1 \cdot ( - 3 n )}{2 \cdot 1}

Simplify

(- n + 3)^{2} - 4 \cdot 1 \cdot (- 3 n) : n + 3

x_{1, 2} = \frac{- ( - n + 3 ) \pm ( n + 3 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - n + 3 ) + n + 3}{2 \cdot 1}, x_{2} = \frac{- ( - n + 3 ) - ( n + 3 )}{2 \cdot 1}

x = \frac{- ( - n + 3 ) + n + 3}{2 \cdot 1} : n

x = \frac{- ( - n + 3 ) - ( n + 3 )}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = n, x = - 3

(x + 4) (x - 3) = - 5 x - 11

x = a x^{2} + b x + c

2 x^{2} + 16 x

2 x^{2} + 42 x - 1080 = 0

2 x^{2} + 12 x

What are the solutions to the equation x^2-(n-3)x-3n=0 ?
The solutions to the equation x^2-(n-3)x-3n=0 are x=n,x=-3
Find the zeros of x^2-(n-3)x-3n=0
The zeros of x^2-(n-3)x-3n=0 are x=n,x=-3