What are the solutions to the equation -3x-9+5x^2=3x ?

The solutions to the equation -3x-9+5x^2=3x are x=(3(1+sqrt(6)))/5 ,x=(3(1-sqrt(6)))/5

Find the zeros of -3x-9+5x^2=3x

The zeros of -3x-9+5x^2=3x are x=(3(1+sqrt(6)))/5 ,x=(3(1-sqrt(6)))/5

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- 3 x - 9 + 5 x^{2} = 3 x

x = \frac{3 ( 1 + 6 )}{5}, x = \frac{3 ( 1 - 6 )}{5}

Decimal Notation

x = 2.06969 \dots, x = - 0.86969 \dots

Solution steps

- 3 x - 9 + 5 x^{2} = 3 x

Move

3 x

to the left side

5 x^{2} - 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

(- 6)^{2} - 4 \cdot 5 (- 9) = 66

x_{1, 2} = \frac{- ( - 6 ) \pm 6 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 6}{2 \cdot 5}, x_{2} = \frac{- ( - 6 ) - 6 6}{2 \cdot 5}

x = \frac{- ( - 6 ) + 6 6}{2 \cdot 5} : \frac{3 ( 1 + 6 )}{5}

x = \frac{- ( - 6 ) - 6 6}{2 \cdot 5} : \frac{3 ( 1 - 6 )}{5}

The solutions to the quadratic equation are:

x = \frac{3 ( 1 + 6 )}{5}, x = \frac{3 ( 1 - 6 )}{5}

y = 3 y^{2}

t^{2} + t - 6 = 0

6 - 2 x^{2} = 9 x + 15

x, 3 x^{2} y = 0

y, x^{2} + y^{2} - 2 z^{2} + z ln (x) = 0

What are the solutions to the equation -3x-9+5x^2=3x ?
The solutions to the equation -3x-9+5x^2=3x are x=(3(1+sqrt(6)))/5 ,x=(3(1-sqrt(6)))/5
Find the zeros of -3x-9+5x^2=3x
The zeros of -3x-9+5x^2=3x are x=(3(1+sqrt(6)))/5 ,x=(3(1-sqrt(6)))/5