What are the solutions to the equation 10a^2+175=-95a ?

The solutions to the equation 10a^2+175=-95a are a=-5/2 ,a=-7

Find the zeros of 10a^2+175=-95a

The zeros of 10a^2+175=-95a are a=-5/2 ,a=-7

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10 a^{2} + 175 = - 95 a

a = - \frac{5}{2}, a = - 7

Decimal Notation

a = - 2.5, a = - 7

Solution steps

10 a^{2} + 175 = - 95 a

Move

95 a

to the left side

10 a^{2} + 175 + 95 a = 0

Write in the standard form

a x^{2} + b x + c = 0

10 a^{2} + 95 a + 175 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 95 \pm 9 5 ^{2} - 4 \cdot 10 \cdot 175}{2 \cdot 10}

9 5^{2} - 4 \cdot 10 \cdot 175 = 45

a_{1, 2} = \frac{- 95 \pm 45}{2 \cdot 10}

Separate the solutions

a_{1} = \frac{- 95 + 45}{2 \cdot 10}, a_{2} = \frac{- 95 - 45}{2 \cdot 10}

a = \frac{- 95 + 45}{2 \cdot 10} : - \frac{5}{2}

a = \frac{- 95 - 45}{2 \cdot 10} : - 7

The solutions to the quadratic equation are:

a = - \frac{5}{2}, a = - 7

3 y^{2} - 4 y - 4 = 0

0 = z^{2} + 2.5 z - 1.5

z^{2} - z + 0.5 = 0

(x - 2 + 5 x) (x + 2 + 5 x) - 5 x = x^{2} + 6

x^{2} + 8 x - 100 = - 7

What are the solutions to the equation 10a^2+175=-95a ?
The solutions to the equation 10a^2+175=-95a are a=-5/2 ,a=-7
Find the zeros of 10a^2+175=-95a
The zeros of 10a^2+175=-95a are a=-5/2 ,a=-7