What are the solutions to the equation 8x^2+16x-3=0 ?

The solutions to the equation 8x^2+16x-3=0 are x=(-4+sqrt(22))/4 ,x=-(4+sqrt(22))/4

Find the zeros of 8x^2+16x-3=0

The zeros of 8x^2+16x-3=0 are x=(-4+sqrt(22))/4 ,x=-(4+sqrt(22))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} + 16 x - 3 = 0

x = \frac{- 4 + 22}{4}, x = - \frac{4 + 22}{4}

Decimal Notation

x = 0.17260 \dots, x = - 2.17260 \dots

Solution steps

8 x^{2} + 16 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

1 6^{2} - 4 \cdot 8 (- 3) = 422

x_{1, 2} = \frac{- 16 \pm 4 22}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 16 + 4 22}{2 \cdot 8}, x_{2} = \frac{- 16 - 4 22}{2 \cdot 8}

x = \frac{- 16 + 4 22}{2 \cdot 8} : \frac{- 4 + 22}{4}

x = \frac{- 16 - 4 22}{2 \cdot 8} : - \frac{4 + 22}{4}

The solutions to the quadratic equation are:

x = \frac{- 4 + 22}{4}, x = - \frac{4 + 22}{4}

x^{2} = \frac{2000000}{3}

0 = 12 x^{2} - 520 x + 4000

x, y = \frac{121}{5} - \frac{1}{5} x^{2}

4 (x^{2} - 30 x + 2500) = 0

6 y^{2} + y - 1 = (y + 5) (y - 1)

What are the solutions to the equation 8x^2+16x-3=0 ?
The solutions to the equation 8x^2+16x-3=0 are x=(-4+sqrt(22))/4 ,x=-(4+sqrt(22))/4
Find the zeros of 8x^2+16x-3=0
The zeros of 8x^2+16x-3=0 are x=(-4+sqrt(22))/4 ,x=-(4+sqrt(22))/4