What are the solutions to the equation 0=x^2+2x+7 ?

The solutions to the equation 0=x^2+2x+7 are x=-1+sqrt(6)i,x=-1-sqrt(6)i

Find the zeros of 0=x^2+2x+7

The zeros of 0=x^2+2x+7 are x=-1+sqrt(6)i,x=-1-sqrt(6)i

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0 = x^{2} + 2 x + 7

x = - 1 + 6 i, x = - 1 - 6 i

Solution steps

0 = x^{2} + 2 x + 7

Switch sides

x^{2} + 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 7 : 26 i

x_{1, 2} = \frac{- 2 \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 6 i}{2 \cdot 1}

x = \frac{- 2 + 2 6 i}{2 \cdot 1} : - 1 + 6 i

x = \frac{- 2 - 2 6 i}{2 \cdot 1} : - 1 - 6 i

The solutions to the quadratic equation are:

x = - 1 + 6 i, x = - 1 - 6 i

2 a^{2} = 25

z^{2} = 90

z^{2} = 9 z

x^{2} - 40 x + 359 = 0

z^{2} = - 7

What are the solutions to the equation 0=x^2+2x+7 ?
The solutions to the equation 0=x^2+2x+7 are x=-1+sqrt(6)i,x=-1-sqrt(6)i
Find the zeros of 0=x^2+2x+7
The zeros of 0=x^2+2x+7 are x=-1+sqrt(6)i,x=-1-sqrt(6)i