What are the solutions to the equation x^2+4x+15/4 =0 ?

The solutions to the equation x^2+4x+15/4 =0 are x=-3/2 ,x=-5/2

Find the zeros of x^2+4x+15/4 =0

The zeros of x^2+4x+15/4 =0 are x=-3/2 ,x=-5/2

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x^{2} + 4 x + \frac{15}{4} = 0

x = - \frac{3}{2}, x = - \frac{5}{2}

Decimal Notation

x = - 1.5, x = - 2.5

Solution steps

x^{2} + 4 x + \frac{15}{4} = 0

Multiply both sides by

4

4 x^{2} + 16 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 \cdot 15 = 4

x_{1, 2} = \frac{- 16 \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 4}{2 \cdot 4}, x_{2} = \frac{- 16 - 4}{2 \cdot 4}

x = \frac{- 16 + 4}{2 \cdot 4} : - \frac{3}{2}

x = \frac{- 16 - 4}{2 \cdot 4} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - \frac{5}{2}

g^{2} + 2 g - 15 = 0

5 r^{2} - 5 r = - 8

x, x^{2} y^{2} = - 1

x^{2} - 14 = 2 x

8 t^{2} - 2 t = 3

What are the solutions to the equation x^2+4x+15/4 =0 ?
The solutions to the equation x^2+4x+15/4 =0 are x=-3/2 ,x=-5/2
Find the zeros of x^2+4x+15/4 =0
The zeros of x^2+4x+15/4 =0 are x=-3/2 ,x=-5/2