What are the solutions to the equation x^2+sqrt(3)x-6=0 ?

The solutions to the equation x^2+sqrt(3)x-6=0 are x=sqrt(3),x=-2sqrt(3)

Find the zeros of x^2+sqrt(3)x-6=0

The zeros of x^2+sqrt(3)x-6=0 are x=sqrt(3),x=-2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 3 x - 6 = 0

x = 3, x = - 23

Decimal Notation

x = 1.73205 \dots, x = - 3.46410 \dots

Solution steps

x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm ( 3 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(3)^{2} - 4 \cdot 1 \cdot (- 6) = 33

x_{1, 2} = \frac{- 3 \pm 3 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 3 3}{2 \cdot 1}, x_{2} = \frac{- 3 - 3 3}{2 \cdot 1}

x = \frac{- 3 + 3 3}{2 \cdot 1} : 3

x = \frac{- 3 - 3 3}{2 \cdot 1} : - 23

The solutions to the quadratic equation are:

x = 3, x = - 23

x, x^{2} + y^{2} - 2 y + 6 = 0

x^{2} + 10 x + 2 = 0

b^{2} - 8 b - 9 = 0

1 8^{2} = (x + 2)^{2} + x

n^{2} - n - 12 = 0

What are the solutions to the equation x^2+sqrt(3)x-6=0 ?
The solutions to the equation x^2+sqrt(3)x-6=0 are x=sqrt(3),x=-2sqrt(3)
Find the zeros of x^2+sqrt(3)x-6=0
The zeros of x^2+sqrt(3)x-6=0 are x=sqrt(3),x=-2sqrt(3)