What are the solutions to the equation 4=2x^2-x+3 ?

The solutions to the equation 4=2x^2-x+3 are x=1,x=-1/2

Find the zeros of 4=2x^2-x+3

The zeros of 4=2x^2-x+3 are x=1,x=-1/2

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4 = 2 x^{2} - x + 3

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

4 = 2 x^{2} - x + 3

Switch sides

2 x^{2} - x + 3 = 4

Move

4

to the left side

2 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 1) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 2}

x = \frac{- ( - 1 ) + 3}{2 \cdot 2} : 1

x = \frac{- ( - 1 ) - 3}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

2 t^{2} - 12 t + 16 = 0

(3 k + 2)^{2} = 100

y, x = 4 - (y - 2)^{2}

x^{2} = 1 5^{2} - 1 2^{2}

k^{2} = - 2 k

What are the solutions to the equation 4=2x^2-x+3 ?
The solutions to the equation 4=2x^2-x+3 are x=1,x=-1/2
Find the zeros of 4=2x^2-x+3
The zeros of 4=2x^2-x+3 are x=1,x=-1/2