What is the answer to 4(r-2)-5(2r-6)=8(r+1)-3(2r+3) ?

The answer to 4(r-2)-5(2r-6)=8(r+1)-3(2r+3) is r= 23/8

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4(r-2)-5(2r-6)=8(r+1)-3(2r+3)

4 (r - 2) - 5 (2 r - 6) = 8 (r + 1) - 3 (2 r + 3)

r = \frac{23}{8}

Decimal Notation

r = 2.875

Solution steps

4 (r - 2) - 5 (2 r - 6) = 8 (r + 1) - 3 (2 r + 3)

Expand

4 (r - 2) - 5 (2 r - 6) : - 6 r + 22

Expand

8 (r + 1) - 3 (2 r + 3) : 2 r - 1

- 6 r + 22 = 2 r - 1

Move

22

to the right side

- 6 r = 2 r - 23

Move

2 r

to the left side

- 8 r = - 23

Divide both sides by

- 8

r = \frac{23}{8}

11 y - 5 y + 6 = - 24 - 9 y

x, 2 x - 3 y = 1

x, 2 x - 3 y = 5

\frac{x}{3} = \frac{( x + 12 )}{9}

x, 4 x + 5 y = 20

What is the answer to 4(r-2)-5(2r-6)=8(r+1)-3(2r+3) ?
The answer to 4(r-2)-5(2r-6)=8(r+1)-3(2r+3) is r= 23/8
Solve for r: 4(r-2)-5(2r-6)=8(r+1)-3(2r+3)
The solution is r= 23/8