What are the solutions to the equation 2x^2-4x=14 ?

The solutions to the equation 2x^2-4x=14 are x=1+2sqrt(2),x=1-2sqrt(2)

Find the zeros of 2x^2-4x=14

The zeros of 2x^2-4x=14 are x=1+2sqrt(2),x=1-2sqrt(2)

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2 x^{2} - 4 x = 14

x = 1 + 22, x = 1 - 22

Decimal Notation

x = 3.82842 \dots, x = - 1.82842 \dots

Solution steps

2 x^{2} - 4 x = 14

Move

14

to the left side

2 x^{2} - 4 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 14) = 82

x_{1, 2} = \frac{- ( - 4 ) \pm 8 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 2}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 8 2}{2 \cdot 2}

x = \frac{- ( - 4 ) + 8 2}{2 \cdot 2} : 1 + 22

x = \frac{- ( - 4 ) - 8 2}{2 \cdot 2} : 1 - 22

The solutions to the quadratic equation are:

x = 1 + 22, x = 1 - 22

\frac{x + 3}{3} - \frac{4}{x + 2} > \frac{x}{3}

a^{2} - 2 a + 1 - b^{2}

\frac{1000 0 ^{2} \cdot 1.5 \cdot 1 0 ^{- 12}}{4}

- 6 x^{2} = 0

x^{2} - 3 + x^{2} y - 3 y

What are the solutions to the equation 2x^2-4x=14 ?
The solutions to the equation 2x^2-4x=14 are x=1+2sqrt(2),x=1-2sqrt(2)
Find the zeros of 2x^2-4x=14
The zeros of 2x^2-4x=14 are x=1+2sqrt(2),x=1-2sqrt(2)