What is the answer to solvefor a,b^2-4ac=0 ?

The answer to solvefor a,b^2-4ac=0 is a=(b^2)/(4c);\quad c\ne 0

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solvefor a,b^2-4ac=0

solve for

a, b^{2} - 4 a c = 0

a = \frac{b ^{2}}{4 c}; c \neq = 0

Solution steps

b^{2} - 4 a c = 0

Move

b^{2}

to the right side

- 4 a c = - b^{2}

Divide both sides by

- 4 c; c \neq = 0

a = \frac{b ^{2}}{4 c}; c \neq = 0

x, x y = 4

x + 7 = 22

s, in = i t i es

x, x - 2 y = 1

x, x - 5 y = 5

What is the answer to solvefor a,b^2-4ac=0 ?
The answer to solvefor a,b^2-4ac=0 is a=(b^2)/(4c);\quad c\ne 0