What is the answer to (x+2)(x+3)=x^2+4x+13 ?

The answer to (x+2)(x+3)=x^2+4x+13 is x=7

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(x+2)(x+3)=x^2+4x+13

(x + 2) (x + 3) = x^{2} + 4 x + 13

x = 7

Solution steps

(x + 2) (x + 3) = x^{2} + 4 x + 13

Expand

(x + 2) (x + 3) : x^{2} + 5 x + 6

x^{2} + 5 x + 6 = x^{2} + 4 x + 13

Move

6

to the right side

x^{2} + 5 x = x^{2} + 4 x + 7

Subtract

x^{2} + 4 x

from both sides

x^{2} + 5 x - (x^{2} + 4 x) = x^{2} + 4 x + 7 - (x^{2} + 4 x)

Simplify

x = 7

x, - 2 x + y = 1

x, 5 x - 2 y = 9

2 b (2 a - x) = x (b - a) + a (x + b)

x, 4 x - y = 8

x, x - 3 y = - 6

What is the answer to (x+2)(x+3)=x^2+4x+13 ?
The answer to (x+2)(x+3)=x^2+4x+13 is x=7
Solve for x: (x+2)(x+3)=x^2+4x+13
The solution is x=7