What are the solutions to the equation (x+3)^2+(x-3)^2=26 ?

The solutions to the equation (x+3)^2+(x-3)^2=26 are x=2,x=-2

Find the zeros of (x+3)^2+(x-3)^2=26

The zeros of (x+3)^2+(x-3)^2=26 are x=2,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 3)^{2} + (x - 3)^{2} = 26

x = 2, x = - 2

Solution steps

(x + 3)^{2} + (x - 3)^{2} = 26

Expand

(x + 3)^{2} + (x - 3)^{2} : 2 x^{2} + 18

2 x^{2} + 18 = 26

Move

26

to the left side

2 x^{2} - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 8) = 8

x_{1, 2} = \frac{- 0 \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 8}{2 \cdot 2}, x_{2} = \frac{- 0 - 8}{2 \cdot 2}

x = \frac{- 0 + 8}{2 \cdot 2} : 2

x = \frac{- 0 - 8}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = 2, x = - 2

4 r^{2} + 64 r + 256

2 x = x - 8

x^{2} - 169 y^{2}

x^{3} + 2 x^{2} > 8 x

- 3 + x = 7

What are the solutions to the equation (x+3)^2+(x-3)^2=26 ?
The solutions to the equation (x+3)^2+(x-3)^2=26 are x=2,x=-2
Find the zeros of (x+3)^2+(x-3)^2=26
The zeros of (x+3)^2+(x-3)^2=26 are x=2,x=-2