What is the answer to (x+3)/8-(x-3}{10}=\frac{x-5)/4-1 ?

The answer to (x+3)/8-(x-3}{10}=\frac{x-5)/4-1 is x=13

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(x+3)/8-(x-3}{10}=\frac{x-5)/4-1

\frac{x + 3}{8} - \frac{x - 3}{10} = \frac{x - 5}{4} - 1

x = 13

Solution steps

\frac{x + 3}{8} - \frac{x - 3}{10} = \frac{x - 5}{4} - 1

Multiply by LCM

5 (x + 3) - 4 (x - 3) = 10 (x - 5) - 40

Expand

5 (x + 3) - 4 (x - 3) : x + 27

Expand

10 (x - 5) - 40 : 10 x - 90

x + 27 = 10 x - 90

Move

27

to the right side

x = 10 x - 117

Move

10 x

to the left side

- 9 x = - 117

Divide both sides by

- 9

x = 13

x, 3 x + 2 y = 14

x, x + 3 y = 0

x, 3 x + 5 y = - 4

x, 3 x + 6 y = 12

\frac{5}{3} k - 3 = \frac{1}{3} + 2 k

What is the answer to (x+3)/8-(x-3}{10}=\frac{x-5)/4-1 ?
The answer to (x+3)/8-(x-3}{10}=\frac{x-5)/4-1 is x=13
Solve for x: (x+3)/8-(x-3}{10}=\frac{x-5)/4-1
The solution is x=13