What is the answer to (x-5)/2+(x-1)/8 =(x-3)/4+(x-4)/3 ?

The answer to (x-5)/2+(x-1)/8 =(x-3)/4+(x-4)/3 is x=13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-5)/2+(x-1)/8 =(x-3)/4+(x-4)/3

\frac{x - 5}{2} + \frac{x - 1}{8} = \frac{x - 3}{4} + \frac{x - 4}{3}

x = 13

Solution steps

\frac{x - 5}{2} + \frac{x - 1}{8} = \frac{x - 3}{4} + \frac{x - 4}{3}

Multiply by LCM

12 (x - 5) + 3 (x - 1) = 6 (x - 3) + 8 (x - 4)

Expand

12 (x - 5) + 3 (x - 1) : 15 x - 63

Expand

6 (x - 3) + 8 (x - 4) : 14 x - 50

15 x - 63 = 14 x - 50

Move

63

to the right side

15 x = 14 x + 13

Move

14 x

to the left side

x = 13

3 x + 5 = 5 x - 15

x, x + y + z = 2

x, x - 3 y = 4

x, 3 x + 5 y = - 15

\frac{a}{4} - 23 = - 17

What is the answer to (x-5)/2+(x-1)/8 =(x-3)/4+(x-4)/3 ?
The answer to (x-5)/2+(x-1)/8 =(x-3)/4+(x-4)/3 is x=13
Solve for x: (x-5)/2+(x-1)/8 =(x-3)/4+(x-4)/3
The solution is x=13