What is the answer to (3x-2)/5-(2x+1}{10}=\frac{6x-3)/2-4 ?

The answer to (3x-2)/5-(2x+1}{10}=\frac{6x-3)/2-4 is x= 25/13

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(3x-2)/5-(2x+1}{10}=\frac{6x-3)/2-4

\frac{3 x - 2}{5} - \frac{2 x + 1}{10} = \frac{6 x - 3}{2} - 4

x = \frac{25}{13}

Solution steps

\frac{3 x - 2}{5} - \frac{2 x + 1}{10} = \frac{6 x - 3}{2} - 4

Multiply by LCM

2 (3 x - 2) - (2 x + 1) = 5 (6 x - 3) - 40

Expand

2 (3 x - 2) - (2 x + 1) : 4 x - 5

Expand

5 (6 x - 3) - 40 : 30 x - 55

4 x - 5 = 30 x - 55

Move

5

to the right side

4 x = 30 x - 50

Move

30 x

to the left side

- 26 x = - 50

Divide both sides by

- 26

x = \frac{25}{13}

x - 18 = 2

x, x + 3 y = 7

- 2.5 (4 x - 4) = - 6

x, 3 x - 2 y = - 4

x, 2 x - y = 9

What is the answer to (3x-2)/5-(2x+1}{10}=\frac{6x-3)/2-4 ?
The answer to (3x-2)/5-(2x+1}{10}=\frac{6x-3)/2-4 is x= 25/13
Solve for x: (3x-2)/5-(2x+1}{10}=\frac{6x-3)/2-4
The solution is x= 25/13