What are the solutions to the equation -6x^2-6x+12=0 ?

The solutions to the equation -6x^2-6x+12=0 are x=-2,x=1

Find the zeros of -6x^2-6x+12=0

The zeros of -6x^2-6x+12=0 are x=-2,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 6 x^{2} - 6 x + 12 = 0

x = - 2, x = 1

Solution steps

- 6 x^{2} - 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 6 ) \cdot 12}{2 ( - 6 )}

(- 6)^{2} - 4 (- 6) \cdot 12 = 18

x_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18}{2 ( - 6 )}, x_{2} = \frac{- ( - 6 ) - 18}{2 ( - 6 )}

x = \frac{- ( - 6 ) + 18}{2 ( - 6 )} : - 2

x = \frac{- ( - 6 ) - 18}{2 ( - 6 )} : 1

The solutions to the quadratic equation are:

x = - 2, x = 1

8 a^{2} + 6 a = - 5

x^{2} + (x - 7)^{2} = (x + 2)^{2}

- 32 t + 100 = 0

5 (4)^{2}

j + 7 > - 6

What are the solutions to the equation -6x^2-6x+12=0 ?
The solutions to the equation -6x^2-6x+12=0 are x=-2,x=1
Find the zeros of -6x^2-6x+12=0
The zeros of -6x^2-6x+12=0 are x=-2,x=1