What are the solutions to the equation 4(3x-2)^2+5=33 ?

The solutions to the equation 4(3x-2)^2+5=33 are x=(sqrt(7)+2)/3 ,x=(-sqrt(7)+2)/3

Find the zeros of 4(3x-2)^2+5=33

The zeros of 4(3x-2)^2+5=33 are x=(sqrt(7)+2)/3 ,x=(-sqrt(7)+2)/3

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4 (3 x - 2)^{2} + 5 = 33

x = \frac{7 + 2}{3}, x = \frac{- 7 + 2}{3}

Decimal Notation

x = 1.54858 \dots, x = - 0.21525 \dots

Solution steps

4 (3 x - 2)^{2} + 5 = 33

Move

5

to the right side

4 (3 x - 2)^{2} = 28

Divide both sides by

4

(3 x - 2)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 2 = 7 : x = \frac{7 + 2}{3}

Solve

3 x - 2 = - 7 : x = \frac{- 7 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 2}{3}, x = \frac{- 7 + 2}{3}

∣ 3 x ∣ < 21

20 x^{2} - 23 x + 6

∣ 2 x - 1 ∣ < 5

225 a^{2} - 36 b^{2}

3 x^{2} - 75

What are the solutions to the equation 4(3x-2)^2+5=33 ?
The solutions to the equation 4(3x-2)^2+5=33 are x=(sqrt(7)+2)/3 ,x=(-sqrt(7)+2)/3
Find the zeros of 4(3x-2)^2+5=33
The zeros of 4(3x-2)^2+5=33 are x=(sqrt(7)+2)/3 ,x=(-sqrt(7)+2)/3