What is the answer to a(x-b)+bx+c=a+b ?

The answer to a(x-b)+bx+c=a+b is x=(a+b-c+ab)/(a+b);\quad a\ne-b

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a(x-b)+bx+c=a+b

a (x - b) + b x + c = a + b

x = \frac{a + b - c + ab}{a + b}; a \neq = - b

Solution steps

a (x - b) + b x + c = a + b

Move

c

to the right side

a (x - b) + b x = a + b - c

Expand

a (x - b) : a x - ab

a x - ab + b x = a + b - c

Move

ab

to the right side

a x + b x = a + b - c + ab

Factor

a x + b x : x (a + b)

x (a + b) = a + b - c + ab

Divide both sides by

a + b; a \neq = - b

x = \frac{a + b - c + ab}{a + b}; a \neq = - b

20 x + 14 + 5 x - 24 = 12 - 21 x - 10

3.5 g - 9.4 = 0.6 + 4.5 g

- 9 n - 10 = 5 n + 8 + 10

x, 2 x - y = - 6

x, x - 2 y = 12

What is the answer to a(x-b)+bx+c=a+b ?
The answer to a(x-b)+bx+c=a+b is x=(a+b-c+ab)/(a+b);\quad a\ne-b