What is the answer to solvefor x,xy+x+y=2020 ?

The answer to solvefor x,xy+x+y=2020 is x=(2020-y)/(y+1);\quad y\ne-1

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solvefor x,xy+x+y=2020

solve for

x, x y + x + y = 2020

x = \frac{2020 - y}{y + 1}; y \neq = - 1

Solution steps

x y + x + y = 2020

Move

y

to the right side

x y + x = 2020 - y

Factor

x y + x : x (y + 1)

x (y + 1) = 2020 - y

Divide both sides by

y + 1; y \neq = - 1

x = \frac{2020 - y}{y + 1}; y \neq = - 1

x, x y - 1 = 0

b, A = \frac{1}{2} h (b + b)

9 n - 11 = 34

8 = - 3 c + 29

\frac{x - 4}{2} + 3 = 4 x

What is the answer to solvefor x,xy+x+y=2020 ?
The answer to solvefor x,xy+x+y=2020 is x=(2020-y)/(y+1);\quad y\ne-1