What are the solutions to the equation -x^2+3=2x+3 ?

The solutions to the equation -x^2+3=2x+3 are x=-2,x=0

Find the zeros of -x^2+3=2x+3

The zeros of -x^2+3=2x+3 are x=-2,x=0

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- x^{2} + 3 = 2 x + 3

x = - 2, x = 0

Solution steps

- x^{2} + 3 = 2 x + 3

Move

3

to the left side

- x^{2} = 2 x

Move

2 x

to the left side

- x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 2}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 2}{2 ( - 1 )} : - 2

x = \frac{- ( - 2 ) - 2}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

x = - 2, x = 0

2 x - 5 > 1

3 m^{2} + 2 m + 1 = 0

(u^{- 1})^{2}

y^{9} - 1 \leq 1

(x - 78) + 43 = 16

What are the solutions to the equation -x^2+3=2x+3 ?
The solutions to the equation -x^2+3=2x+3 are x=-2,x=0
Find the zeros of -x^2+3=2x+3
The zeros of -x^2+3=2x+3 are x=-2,x=0