What is the answer to (x+2)2+x(x+1)=(x+3)2+x^2 ?

The answer to (x+2)2+x(x+1)=(x+3)2+x^2 is x=2

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(x+2)2+x(x+1)=(x+3)2+x^2

(x + 2) 2 + x (x + 1) = (x + 3) 2 + x^{2}

x = 2

Solution steps

(x + 2) \cdot 2 + x (x + 1) = (x + 3) \cdot 2 + x^{2}

Expand

(x + 2) \cdot 2 + x (x + 1) : x^{2} + 3 x + 4

Expand

(x + 3) \cdot 2 + x^{2} : 2 x + 6 + x^{2}

x^{2} + 3 x + 4 = 2 x + 6 + x^{2}

Move

4

to the right side

x^{2} + 3 x = x^{2} + 2 x + 2

Subtract

x^{2} + 2 x

from both sides

x^{2} + 3 x - (x^{2} + 2 x) = x^{2} + 2 x + 2 - (x^{2} + 2 x)

Simplify

x = 2

x, 7 x + y = 5

12 x - 4 = 3 x

5 x + 2 = 3 x + 7

x, 20 y - 4 x = - 160

x, x + 2 y = 14

What is the answer to (x+2)2+x(x+1)=(x+3)2+x^2 ?
The answer to (x+2)2+x(x+1)=(x+3)2+x^2 is x=2
Solve for x: (x+2)2+x(x+1)=(x+3)2+x^2
The solution is x=2