What is the answer to (x+a)(x-b)-(x+b)(x-2a)=b(a-2)+3a ?

The answer to (x+a)(x-b)-(x+b)(x-2a)=b(a-2)+3a is x=1;\quad a\ne (2b)/3

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(x+a)(x-b)-(x+b)(x-2a)=b(a-2)+3a

(x + a) (x - b) - (x + b) (x - 2 a) = b (a - 2) + 3 a

x = 1; a \neq = \frac{2 b}{3}

Solution steps

(x + a) (x - b) - (x + b) (x - 2 a) = b (a - 2) + 3 a

Expand

b (a - 2) : ab - 2 b

3 a x - 2 b x + ab = ab - 2 b + 3 a

Expand

(x + a) (x - b) - (x + b) (x - 2 a) : 3 a x - 2 b x + ab

3 a x - 2 b x + ab = ab - 2 b + 3 a

Move

ab

to the right side

3 a x - 2 b x = 3 a - 2 b

Factor

3 a x - 2 b x : x (3 a - 2 b)

x (3 a - 2 b) = 3 a - 2 b

Divide both sides by

3 a - 2 b; a \neq = \frac{2 b}{3}

x = 1; a \neq = \frac{2 b}{3}

- 14 w + 13 w = - 11

- 10 y + 18 = - 3 (5 y - 7) + 5 y

5 + 3 x = 12 - x

- 9 d + 12 d = 15

12 x - 6 = 0

What is the answer to (x+a)(x-b)-(x+b)(x-2a)=b(a-2)+3a ?
The answer to (x+a)(x-b)-(x+b)(x-2a)=b(a-2)+3a is x=1;\quad a\ne (2b)/3