What is the answer to m(n-x)-m(n-1)=m(mx-a) ?

The answer to m(n-x)-m(n-1)=m(mx-a) is x=(a+1)/(m+1);\quad m\ne 0,m\ne-1

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m(n-x)-m(n-1)=m(mx-a)

m (n - x) - m (n - 1) = m (m x - a)

x = \frac{a + 1}{m + 1}; m \neq = 0, m \neq = - 1

Solution steps

m (n - x) - m (n - 1) = m (m x - a)

Expand

m (n - x) - m (n - 1) : - m x + m

Expand

m (m x - a) : m^{2} x - ma

- m x + m = m^{2} x - ma

Move

m

to the right side

- m x = m^{2} x - ma - m

Move

m^{2} x

to the left side

- m x - m^{2} x = - ma - m

Factor

- m x - m^{2} x : - m x (1 + m)

- m x (1 + m) = - ma - m

Divide both sides by

- m (1 + m); m \neq = 0, m \neq = - 1

x = \frac{a + 1}{m + 1}; m \neq = 0, m \neq = - 1

- \frac{2}{3} = \frac{x}{30}

x, x + y - 4 = 0

x, 3 x + 2 y = - 8

x, x e^{y} = x - y

x, x + y = 11

What is the answer to m(n-x)-m(n-1)=m(mx-a) ?
The answer to m(n-x)-m(n-1)=m(mx-a) is x=(a+1)/(m+1);\quad m\ne 0,m\ne-1