What is the answer to solvefor s,v^2=u^2+2as ?

The answer to solvefor s,v^2=u^2+2as is s=(v^2-u^2)/(2a);\quad a\ne 0

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solvefor s,v^2=u^2+2as

solve for

s, v^{2} = u^{2} + 2 a s

s = \frac{v ^{2} - u ^{2}}{2 a}; a \neq = 0

Solution steps

v^{2} = u^{2} + 2 a s

Switch sides

u^{2} + 2 a s = v^{2}

Move

u^{2}

to the right side

2 a s = v^{2} - u^{2}

Divide both sides by

2 a; a \neq = 0

s = \frac{v ^{2} - u ^{2}}{2 a}; a \neq = 0

x, 2 x - 2 y = 0

y = 3^{- 1}

x, 2 x + y = 16

- 6 = - \frac{5}{2} (6) + b

y, x = - y

What is the answer to solvefor s,v^2=u^2+2as ?
The answer to solvefor s,v^2=u^2+2as is s=(v^2-u^2)/(2a);\quad a\ne 0